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Direct selection involves inoculating cells onto growth media on which


A) the mutant but not the parental cell type will grow.
B) the mutation will be reversed.
C) the nutrients necessary for mutation to occur are present.
D) the mutagen is present.

E) C) and D)
F) A) and B)

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To maximize the number of thymine dimer mutations following UV exposure, should you keep a plate of fungal cells in the dark, in the light, or does it matter at all?


A) The dark-light will activate the photorepair systems that can break thymine dimers induced by UV light.
B) The light-it's important to keep on producing the thymine dimers by keeping the plate exposed to light as much as possible.
C) It's best to alternate light and dark every hour to increase the chances that thymine dimers will form in the fungal cells, but still keep the photorepair systems from correcting them as they are formed.
D) It doesn't matter-fungal cells don't possess the enzymes needed for photorepair of thymine dimers.They're only in prokaryotes.

E) A) and D)
F) B) and C)

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Insertion sequences


A) are the simplest type of transposon.
B) code for a transposase enzyme.
C) are characterized by an inverted repeat.
D) can produce pili.
E) are the simplest type of transposon, code for a transposase enzyme AND are characterized by an inverted repeat.

F) B) and E)
G) A) and E)

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Plasmids often carry the information for antibiotic resistance.

A) True
B) False

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Indirect selection


A) is necessary to isolate auxotrophic mutants.
B) uses media on which the mutant but not the parental cell type will grow.
C) uses media that reverses the mutation.
D) uses media upon which neither the parental cell type or mutant grows.
E) is necessary to isolate auxotrophic mutants AND uses media upon which neither the parental cell type or mutant grows.

F) All of the above
G) A) and E)

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X-rays


A) have no effect on DNA.
B) cause thymine trimers.
C) cause single and double strand breaks in DNA molecules.
D) make the DNA radioactive.

E) None of the above
F) All of the above

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Double-stranded DNA enters the recipient cell during transformation.

A) True
B) False

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False

Replica plating


A) is useful for direct selection.
B) is useful for identifying auxotrophs.
C) uses media on which the mutant will not grow and the parental cell type will.
D) is used to store strains of bacteria.
E) is useful for identifying auxotrophs AND uses media on which the mutant will not grow and the parental cell type will.

F) None of the above
G) A) and D)

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E

Every 24 hours, every genome in every cell of the human body is damaged 10,000 times or more. Given the possible DNA repair mechanisms, which order listed below would be most effective at repairing these as quickly as possible in order to prevent mutations from being carried forward in DNA replication?


A) proofreading by DNA polymerase, glycosylase enzyme activities, excision repair, photoreactivation, SOS repair
B) SOS repair, photoreactivation, excision repair, glycosylase enzyme activities, proofreading by DNA polymerase
C) photoreactivation, SOS repair, proofreading by DNA polymerase, glycosylase enzyme activities, excision repair
D) glycosylase enzyme activities, SOS repair, photoreactivation, proofreading by DNA polymerase, excision repair

E) A) and B)
F) B) and D)

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Competent cells


A) are able to take up naked DNA.
B) are antibiotic resistant.
C) occur naturally.
D) can be created in the laboratory.
E) are able to take up naked DNA, occur naturally AND can be created in the laboratory.

F) A) and B)
G) A) and E)

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Mutations


A) may occur spontaneously.
B) occurring at one gene are often coupled to mutation of another gene.
C) are more likely to be killed by using 2 antibiotics.
D) are always harmful.
E) may occur spontaneously AND are more likely to be killed by using 2 antibiotics.

F) B) and C)
G) A) and B)

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Bacteria that have properties of both the donor and recipient cells are the result of


A) UV light.
B) SOS repair.
C) frame shift mutations.
D) genetic recombination.

E) A) and D)
F) A) and B)

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A clever technique that streamlines the identification of auxotrophic mutants is


A) gas chromatography.
B) replica plating.
C) direct selection.
D) reversion.

E) A) and B)
F) A) and C)

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The Ames test is useful as a rapid screening test to identify those compounds that


A) will respond to chemical agents.
B) have a high probability of being carcinogenic.
C) respond to the deletion of DNAses.
D) will protect an organism from cancer.
E) will respond to chemical agents AND will protect an organism from cancer.

F) A) and B)
G) A) and C)

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B

Chemical mutagens that mimic the naturally occurring bases are called


A) nitrogen mustards.
B) alkylating agents.
C) base analogs.
D) nitrous oxide.

E) None of the above
F) C) and D)

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Among the easiest of the mutations to isolate are those which


A) involve haploid chromosomes.
B) involve antibiotic resistance.
C) allow populations to be measured.
D) use an indirect method for measurement.
E) involve haploid chromosomes AND involve antibiotic resistance.

F) A) and B)
G) A) and E)

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In conjugation the donor cell is recognized by the presence of


A) an F plasmid.
B) a Y chromosome.
C) diploid chromosomes.
D) an SOS response.
E) an F plasmid AND diploid chromosomes.

F) C) and E)
G) C) and D)

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Segments of DNA capable of moving from one area in the DNA to another are called


A) base analogs.
B) intercalating agents.
C) transposons.
D) palindromic sequences.

E) A) and C)
F) None of the above

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The largest group of chemical mutagens consists of


A) radiation.
B) base analogs.
C) nitrous acid.
D) alkylating agents.

E) None of the above
F) A) and D)

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Nitrous acid most frequently causes mutations by


A) substituting oxygen for hydrogen bonds.
B) converting keto groups to amino groups.
C) altering the bonding ratios of nitrogen bases.
D) converting cytosine to uracil.

E) A) and D)
F) All of the above

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