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The between-group variance and the error variance are sometimes referred to as:


A) ANOVA summary table
B) mean squares
C) main effects
D) interaction effects

E) None of the above
F) All of the above

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A Two-Way ANOVA Summary Table is shown below. A Two-Way ANOVA Summary Table is shown below. The critical value for the F test using d.f.N.= 2, and d.f.D = 36 is 3.26.Then: A) Only the null hypothesis concerning Factor A should be rejected B) Only the null hypothesis concerning Factor B should be rejected C) Only the null hypothesis concerning Factor A and the Interaction (AxB) effect should be rejected D) All of the null hypotheses should be accepted The critical value for the F test using A Two-Way ANOVA Summary Table is shown below. The critical value for the F test using d.f.N.= 2, and d.f.D = 36 is 3.26.Then: A) Only the null hypothesis concerning Factor A should be rejected B) Only the null hypothesis concerning Factor B should be rejected C) Only the null hypothesis concerning Factor A and the Interaction (AxB) effect should be rejected D) All of the null hypotheses should be accepted d.f.N.= 2, and d.f.D = 36 is 3.26.Then:


A) Only the null hypothesis concerning Factor A should be rejected
B) Only the null hypothesis concerning Factor B should be rejected
C) Only the null hypothesis concerning Factor A and the Interaction (AxB) effect should be rejected
D) All of the null hypotheses should be accepted

E) None of the above
F) B) and C)

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Complete the formula for the sum of squares between groups: Complete the formula for the sum of squares between groups: A) B) C) D)


A) Complete the formula for the sum of squares between groups: A) B) C) D)
B) Complete the formula for the sum of squares between groups: A) B) C) D)
C) Complete the formula for the sum of squares between groups: A) B) C) D)
D) Complete the formula for the sum of squares between groups: A) B) C) D)

E) A) and C)
F) A) and B)

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A researcher is performing a two-way ANOVA using two factors.The first factor has 4 levels and the second factor has 10 levels.In the ANOVA Summary Table, the degrees of freedom for the interaction Between the first and second factors will be:


A) 27
B) 30
C) 36
D) 40

E) B) and D)
F) A) and D)

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A diet centre wants to test three different methods for losing weight to determine if the average weight loss (reported in pounds/week) for each method is the same.The results for the three methods are given below.Assuming that there is a significant difference between the three methods, use the Tukey test to determine if there is a significant difference between each pair of methods.Let A diet centre wants to test three different methods for losing weight to determine if the average weight loss (reported in pounds/week) for each method is the same.The results for the three methods are given below.Assuming that there is a significant difference between the three methods, use the Tukey test to determine if there is a significant difference between each pair of methods.Let 0.05. 0.05. A diet centre wants to test three different methods for losing weight to determine if the average weight loss (reported in pounds/week) for each method is the same.The results for the three methods are given below.Assuming that there is a significant difference between the three methods, use the Tukey test to determine if there is a significant difference between each pair of methods.Let 0.05.

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The critical q value for v = 15 and k = ...

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The ANOVA technique is an abbreviation for the following term:


A) analysis of variance
B) variance
C) Scheffé test
D) Tukey test

E) B) and D)
F) All of the above

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Complete the formula for the Tukey test: q =


A) Complete the formula for the Tukey test: q = A) B) C) D)
B) Complete the formula for the Tukey test: q = A) B) C) D)
C) Complete the formula for the Tukey test: q = A) B) C) D)
D) Complete the formula for the Tukey test: q = A) B) C) D)

E) A) and B)
F) None of the above

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A researcher is comparing three groups of the same size.The sample mean of the first group is 12, the sample mean of the second group is 14, and the sample mean of the third group is 16.If the Tukey q-test Value for comparing group 1 with group 2 is 2.6, then the Tukey q-test value for comparing group 2 with Group 3 will be:


A) 2.6
B) 5.2
C) 10.4
D) Cannot be determined with the information given

E) C) and D)
F) A) and C)

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This experiment is best described as a(n) :


A) randomized survey.
B) completely randomized design.
C) factorial treatment design carried out in a completely randomized experimental design.
D) observational study.

E) A) and B)
F) A) and C)

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In the Tukey test, if In the Tukey test, if = 6 for a group of siz = 7, = 14 for a group of size = 7, and the within-group variance = 28, then the q test value for comparing group 2 to group 4 is: A) -0.01 B) -0.29 C) -1.51 D) -4.00 = 6 for a group of siz In the Tukey test, if = 6 for a group of siz = 7, = 14 for a group of size = 7, and the within-group variance = 28, then the q test value for comparing group 2 to group 4 is: A) -0.01 B) -0.29 C) -1.51 D) -4.00 = 7, In the Tukey test, if = 6 for a group of siz = 7, = 14 for a group of size = 7, and the within-group variance = 28, then the q test value for comparing group 2 to group 4 is: A) -0.01 B) -0.29 C) -1.51 D) -4.00 = 14 for a group of size In the Tukey test, if = 6 for a group of siz = 7, = 14 for a group of size = 7, and the within-group variance = 28, then the q test value for comparing group 2 to group 4 is: A) -0.01 B) -0.29 C) -1.51 D) -4.00 = 7, and the within-group variance In the Tukey test, if = 6 for a group of siz = 7, = 14 for a group of size = 7, and the within-group variance = 28, then the q test value for comparing group 2 to group 4 is: A) -0.01 B) -0.29 C) -1.51 D) -4.00 = 28, then the q test value for comparing group 2 to group 4 is:


A) -0.01
B) -0.29
C) -1.51
D) -4.00

E) A) and D)
F) None of the above

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What would the Tukey test value be for comparing the means of machine B and machine C at What would the Tukey test value be for comparing the means of machine B and machine C at ? A) -1.61 B) -1.17 C) -7.72 D) -4.46 ?


A) -1.61
B) -1.17
C) -7.72
D) -4.46

E) All of the above
F) None of the above

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A portion of an ANOVA summary table is shown below.What is the F-test value? A portion of an ANOVA summary table is shown below.What is the F-test value? A) 0.15 B) 0.47 C) 6.59 D) 2.13


A) 0.15
B) 0.47
C) 6.59
D) 2.13

E) B) and C)
F) All of the above

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The degrees of freedom for error are:


A) 14
B) 24
C) 29
D) 30

E) All of the above
F) None of the above

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The figure below is an example of what type of interaction? The figure below is an example of what type of interaction? A) disordinal interaction B) ordinal interaction C) There is no interaction because the lines do not cross.


A) disordinal interaction
B) ordinal interaction
C) There is no interaction because the lines do not cross.

D) None of the above
E) A) and C)

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Is there a significant difference between the means for vending machines A, B, and C?


A) Yes, there is a significant difference between the means.
B) No, there is no significant difference between the means.
C) The F-test cannot be used to answer whether or not there is a significant difference between the means.
D) The Scheffé test needs to be performed in order to determine whether or not there is a significant difference between the means.

E) A) and B)
F) B) and D)

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A vending machine company wants to check three of its machines to determine if they are properly dispensing 12 ounces of coffee.The data are given below. A vending machine company wants to check three of its machines to determine if they are properly dispensing 12 ounces of coffee.The data are given below. -What is the grand mean for the data given above? A) 12.08 B) 11.96 C) 11.82 D) 11.85 -What is the grand mean for the data given above?


A) 12.08
B) 11.96
C) 11.82
D) 11.85

E) None of the above
F) B) and D)

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To find the critical value for the Tukey test, the number of means, k, and the degrees of freedom associated with the between-group variance, n, are needed.

A) True
B) False

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A researcher is performing a two-way ANOVA using two factors.The first factor has 4 levels and the second factor also has 4 levels.In the ANOVA Summary Table, the degrees of freedom for the first and Second factors will be:


A) 4 d.f.for the first factor and 4 d.f.for the second factor
B) 3 d.f.for the first factor and 3 d.f.for the second factor
C) 5 d.f.for the first factor and 5 d.f.for the second factor
D) 16 d.f.for the first factor and 16 d.f.for the second factor

E) None of the above
F) A) and B)

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In the Scheffé test, if In the Scheffé test, if = 6 for a group of size n2 = 7, = 14 for a group of size n4 = 7, and the within-group variance = 14, then the FS test value for comparing these two groups is equal to: A) -2.00 B) 16.00 C) 4.57 D) 10.29 = 6 for a group of size n2 = 7, In the Scheffé test, if = 6 for a group of size n2 = 7, = 14 for a group of size n4 = 7, and the within-group variance = 14, then the FS test value for comparing these two groups is equal to: A) -2.00 B) 16.00 C) 4.57 D) 10.29 = 14 for a group of size n4 = 7, and the within-group variance In the Scheffé test, if = 6 for a group of size n2 = 7, = 14 for a group of size n4 = 7, and the within-group variance = 14, then the FS test value for comparing these two groups is equal to: A) -2.00 B) 16.00 C) 4.57 D) 10.29 = 14, then the FS test value for comparing these two groups is equal to:


A) -2.00
B) 16.00
C) 4.57
D) 10.29

E) B) and D)
F) C) and D)

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Assume that the conclusion from an ANOVA is that the null hypothesis is rejected; in other words, the 7 population means (from samples of the same size) are not all equal.We should expect that:


A) all 21 of the comparisons of means Assume that the conclusion from an ANOVA is that the null hypothesis is rejected; in other words, the 7 population means (from samples of the same size) are not all equal.We should expect that: A) all 21 of the comparisons of means ould be significant using the Tukey test. B) at least 7 of the comparisons of mean ould be significant using the Tukey test. C) at least 4 of the comparisons of means ould be significant using the Tukey test. D) at least 1 of the comparisons of means ould be significant using the Tukey test. ould be significant using the Tukey test.
B) at least 7 of the comparisons of mean Assume that the conclusion from an ANOVA is that the null hypothesis is rejected; in other words, the 7 population means (from samples of the same size) are not all equal.We should expect that: A) all 21 of the comparisons of means ould be significant using the Tukey test. B) at least 7 of the comparisons of mean ould be significant using the Tukey test. C) at least 4 of the comparisons of means ould be significant using the Tukey test. D) at least 1 of the comparisons of means ould be significant using the Tukey test. ould be significant using the Tukey test.
C) at least 4 of the comparisons of means Assume that the conclusion from an ANOVA is that the null hypothesis is rejected; in other words, the 7 population means (from samples of the same size) are not all equal.We should expect that: A) all 21 of the comparisons of means ould be significant using the Tukey test. B) at least 7 of the comparisons of mean ould be significant using the Tukey test. C) at least 4 of the comparisons of means ould be significant using the Tukey test. D) at least 1 of the comparisons of means ould be significant using the Tukey test. ould be significant using the Tukey test.
D) at least 1 of the comparisons of means Assume that the conclusion from an ANOVA is that the null hypothesis is rejected; in other words, the 7 population means (from samples of the same size) are not all equal.We should expect that: A) all 21 of the comparisons of means ould be significant using the Tukey test. B) at least 7 of the comparisons of mean ould be significant using the Tukey test. C) at least 4 of the comparisons of means ould be significant using the Tukey test. D) at least 1 of the comparisons of means ould be significant using the Tukey test. ould be significant using the Tukey test.

E) A) and C)
F) A) and D)

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