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We know from research that poverty is a criminogenic risk factor. You select a random sample of 50 adolescents (age 24 and younger) with a criminal record who are still living with their parents from a diverse neighborhood in Orlando (FL) (with known household income/year). You group them into four categories: poverty ($0-$23,000; low income ($23,001-$35,000); lower middle class ($35,000-$55,000); upper middle class ($55,001-$150,000), and high income ($150,001+). You are interested to find whether the average age of onset (understood as a conviction; FL has no minimum age for criminal responsibility) varies between individuals from different socioeconomic backgrounds. You select an alpha level of 0.05. The results are to be found in the table below.  Poverty  Low  income  Lower  middle  class  Upper  middle  class  High  income 11916131612151515171316141618161618181781817141511131721119111120157132419211015211517822181716\begin{array} { | r | r | r | r | r | } \hline { \text { Poverty } } & { \begin{array} { l } \text { Low } \\\text { income }\end{array} } & \begin{array} { l } \text { Lower } \\\text { middle } \\\text { class }\end{array} & \begin{array} { l } \text { Upper } \\\text { middle } \\\text { class }\end{array} & { \begin{array} { l } \text { High } \\\text { income }\end{array} } \\\hline 11 & 9 & 16 & 13 & 16 \\\hline 12 & 15 & 15 & 15 & 17 \\\hline 13 & 16 & 14 & 16 & 18 \\\hline 16 & 16 & 18 & 18 & 17 \\\hline 8 & 18 & 17 & 14 & 15 \\\hline 11 & 13 & 17 & 21 & 11 \\\hline 9 & 11 & 11 & 20 & 15 \\\hline 7 & 13 & 24 & 19 & 21 \\\hline 10 & 15 & 21 & 15 & 17 \\\hline 8 & 22 & 18 & 17 & 16 \\\hline\end{array} a. What is the IV and what is the DV? Also indicate the level of measurement for each variable. b. State your null and alternative hypotheses. c. Compute: i. The group mean. ii. Grand mean. iii. Standard deviation for each group. iv. Sum of squares. v. The degrees of freedom (within and between). vi. F. d. State the decision rule e. Make a decision and interpret your findings. f. Use the Scheffé test to determine which means (if any) significantly differ from each other.

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Prostitution is illegal in all states of the United States (except in some counties in Nevada). You are interested to find whether there is a relationship between gender (male/female/transgender) and attitudes regarding the legal status of prostitution (legalize/decriminalize/criminalize). You draw a random sample of 450 individuals over the age of 18 who are residents of Texas. The results of your survey are presented below. You set an alpha level of 0.05. a. Identify the independent and dependent variables and indicate the level of measurement. b. Compute the percentages for every cell. c. State your null hypothesis and your alternative hypothesis. d. Compute the degrees of freedom. e. State your decision rule. f. Compute expected frequencies for each cell. g. Compute chi square. h. Interpret your findings.  Some high  High school  school  graduate  College/university  Legalize 156339117 Decriminalize 2910451184 Criminalize 51673114995234121450\begin{array}{|l|r|r|r|r|}\hline &\text { Some high }&\text { High school } &&\\&\text { school }&\text { graduate }& \text { College/university }&\\\hline \text { Legalize } & 15 & 63 & 39 & 117 \\\hline \text { Decriminalize } & 29 & 104 & 51 & 184 \\\hline \text { Criminalize } & 51 & 67 & 31 & 149 \\\hline & 95 & 234 & 121 & 450 \\\hline\end{array}

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a. IV = gender: male, female, transgender (nominal). DV = legal status: legalize, decriminalize, criminalize (nominal). b. 11ede0f0_1d7b_5c07_8d10_57db152774b1_TBO1348_00 c. H0: There is no relationship between one's level of education and one's attitudes toward the legal status of prostitution (legalize, decriminalize, criminalize). H1: There is a relationship between one's level of education and one's attitudes toward the legal status of prostitution (legalize, decriminalize, criminalize). d. df = (c - 1)(r - 1) = (3 - 1)(3 - 1) = 4. e. You reject the null hypothesis if x2 is greater than 9.488. f. E(A) = (95 × 117)/450 = 24.7 E(B) = (234 × 117)/450 = 60.84 E(C) = (121 × 117)/450 = 31.46 E(D) = (95 × 184)/450 = 38.84 E(E) = (234 × 184)/450 = 95.68 E(F) = (121 × 184)/450 = 49.48 E(G) = (95 × 149)/450 = 31.46 E(H) = (234 × 149)/450 = 77.48 E(I) = (121 × 149)/450 = 40.06 g. \[\chi ^ { 2 } = \Sigma \frac { ( O - E ) ^ { 2 } } { E } = 24.559\] \(\begin{array}{|l|r|r|r|r|r|} \hline&&&&& (O- \\ \text { Cell } & O & E&O-E & (O-E)^{2}&E^{2} / E \\ \hline \mathrm{A} & 15 & 24.7 & -9.7 & 94.09 & 3.809 \\ \hline \mathrm{B} & 63 & 60.84 & 2.16 & 4.6656 & 0.077 \\ \hline \mathrm{C} & 39 & 31.46 & 7.54 & 56.8516 & 1.807 \\ \hline \mathrm{D} & 29 & 38.84 & -9.84 & 96.8256 & 2.493 \\ \hline \mathrm{E} & 104 & 95.68 & 8.32 & 69.2224 & 0.723 \\ \hline \mathrm{F} & 51 & 49.48 & 1.52 & 2.3104 & 0.047 \\ \hline \mathrm{G} & 51 & 31.46 & 19.54 & 381.8116 & 12.136 \\ \hline \mathrm{H} & 67 & 77.48 & -10.48 & 109.8304 & 1.418 \\ \hline \mathrm{I} & 31 & 40.06 & -9.06 & 82.0836 & 2.049 \\ \hline & & & & \sum & 24.559 \\ \hline \end{array}\) h. You reject your null hypothesis because χ2(4) = 24.599, p > 0.05. There is a statistically significant relationship between level of education and attitudes toward the legal status of prostitution. Whereas 15.79% of individuals with some high school are in favor of legalizing prostitution, 26.92% of high school graduates and 32.23% of college/university students are. Also, whereas only 25.62% of college/university students and 28.64% of high school graduates are in favor of keeping prostitution illegal, 53.68 of individuals with some high school education are pro-criminalization.

Let's assume that you want to examine the relationship between the number of times a person has been bullied in his/her entire life and his/her level of self-esteem (low, moderate, high). You are not quite sure which statistical test of significance you want to use but decide to go with a chi square test of independence because the formulas are more understandable to you. a. Identify the IV and indicate the level of measurement. b. Identify the DV and indicate the level of measurement. c. Reflect on your decision and state whether the test you chose has been the most appropriate one to use. Also, explain your decision.

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Although the social climate surrounding sexual identity is slowly changing toward more tolerance, individuals who are female or transsexual still experience stigma regarding their sexual identity. Assume you have a master list of students enrolled in a large public high school in Portland (OR) and the list also includes their sexual identity. You randomly select 10 students who self-identify as female, 10 who self-identify as male, and 10 who self-identify as transgender. You want to know how accepted they feel by their teachers (with 1 indicating feeling marginalized and 10 indicating a feeling of being 100% accepted). You select an alpha level of 0.05. The results are presented in the table below.  Male Female Transgender 8957835106952101076842774457103358\begin{array}{l}\begin{array} { c c c } \text { Male}&\text { Female}&\text { Transgender }\\8 & 9 & 5 \\7 & 8 & 3 \\5 & 10 & 6 \\9 & 5 & 2 \\10 & 10 & 7 \\6 & 8 & 4 \\2 & 7 & 7 \\4 & 4 & 5 \\7 & 10 & 3 \\3 & 5 & 8\end{array}\end{array} a. What is the IV and what is the DV? Also indicate the level of measurement for each variable. b. State your null and alternative hypotheses. c. Compute: i. The group mean. ii. Grand mean. iii. Standard deviation for each group. iv. Sum of squares. v. The degrees of freedom (within and between). vi. F. d. State the decision rule. e. Make a decision and interpret your findings. f. Use the Scheffé test to determine which means (if any) significantly differ from each other.

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You calculated chi square for several cases that have a table greater than 2 × 2. To determine the strength of the relationship, calculate Cramer's V and interpret your results. a. χ2 = 39.56; n = 166; 3 rows and 3 columns b. χ2 = 22.15; n = 123; 2 rows and 3 columns c. χ2 = 15.26; n = 213; 4 rows and 3 columns d. χ2 = 44.13; n = 286; 3 rows and 5 columns e. χ2 = 10.22; n = 145; 3 rows and 4 columns f. χ2 = 29.36; n = 226; 6 rows and 5 columns

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Let's assume you randomly draw three samples of correction officers from a single facility (50 black/50 white/50 other). You aim to find whether they have ever been a victim of sexual assault or harassment within the correction facility (yes/no). Your friend tells you to run an ANOVA to determine whether there is a difference between white, black, and other correction officers. Will you follow your friends' suggestion? Explain.

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You've learned in your criminology class that low self-control is, according to Gottfredson and Hirschi (1990), a strong predictor for criminal behavior. You have administered a survey with a random sample of 350 high school students determining their level of self-control and you have categorized your findings into low self-control and high self-control. You also asked the participants whether they have ever been in contact with the criminal justice system (yes/no). Now you want to learn whether there is indeed a relationship between low self-control and criminal behavior. The results of your survey are presented in the table below. You set your alpha level at 0.05. a. .Identify the independent and dependent variables and indicate the level of measurement for each variable. b. Compute the percentages for every cell. c. State your null hypothesis and your alternative hypotheses. d. Compute the degrees of freedom. e. State your decision rule. f. Compute expected frequencies for each cell. g. Compute chi square. h.Interpret your findings. YesNoLoW self-control5763120High self-control69161230126224350\begin{array}{c}\begin{array}{|l|}\hline \\\\\hline \text {Yes}\\\hline \text {No}\\\hline \\\hline \end{array}\begin{array}{l|}\hline \text {LoW self-}\\ \text {control}\\\hline 57 \\\hline 63 \\\hline 120 \\\hline\end{array}\begin{array}{l|}\hline \text {High self-}\\ \text {control}\\\hline69 \\ \hline 161 \\\hline 230 \\ \hline\end{array}\begin{array}{l|}\hline\\\\\hline 126 \\\hline 224 \\\hline 350 \\\hline\end{array} \end{array}

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a. IV = level of self-control (ordinal). DV = ever in contact with the criminal justice system (nominal). b. \[\begin{array} { | l | l | l | r | } \hline & \begin{array} { l } \text { Low self- } \\ \text { control } \end{array} & \begin{array} { l } \text { High self- } \\ \text { control } \end{array} & \\ \hline & \mathrm { A } & \mathrm { B } & 126 \\ \text { Yes } & 57 ( 47.5 \% ) & 69 ( 30 \% ) & ( 36 \% ) \\ \hline & \mathrm { C } & \mathrm { D } & 224\\ \text { No } & 63 ( 52.5 \% ) & 161 ( 70 \% ) & \begin{array} { r } \\ ( 64 \% ) \end{array} \\ \hline && & 350 \\ & 120 ( 100 \% ) & 230 ( 100 \% ) & ( 100 \% ) \\ \hline \end{array}\] c. H0: There is no relationship between one's level of self-control and criminal behavior. H1: There is a relationship between one's level of self-control and criminal behavior. d. df = (c - 1)(r - 1) = (2 - 1)(2 - 1) = 1. e. You reject the null hypothesis if x2 is greater than 3.841. f. E(A) = (120 × 126)/350 = 43.2 E(B) = (230 × 126)/350 = 82.8 E(C) = (120 × 224)/350 = 76.8 E(D) = (230 × 224)/350 = 147.2 g. \[\chi ^ { 2 } = \Sigma \frac { ( O - E ) ^ { 2 } } { E } = 10.482\] \(\begin{array}{|l|c|c|r|r|r|} \hline&&&&{(O-} & {(O-}\\ \text { Cell } & O & E & O-E &E)^{\mathbf{2}} &{E)^{\mathbf{2}} / E} \\ \hline \mathrm{A} & 57 & 43.2 & 13.8 & 190.44 & 4.408 \\ \hline \mathrm{B} & 69 & 82.8 & -13.8 & 190.44 & 2.300 \\ \hline \mathrm{C} & 63 & 76.8 & -13.8 & 190.44 & 2.480 \\ \hline \mathrm{D} & 161 & 147.2 & 13.8 & 190.44 & 1.294 \\ \hline & & & & \sum & 10.482 \\ \hline \end{array}\) h. You reject the null hypothesis (alpha 0.05) because x2 (10.48) is greater than 3.841, meaning that there is a statistically significant relationship between one's level of self-control and criminal behavior, χ2(1) = 10.48, p < 0.05. Although 47.5% of high school students with a low level of self-control have been in contact with the criminal justice system, only 30% of high-school students with a high level of self-control have been. You select an alpha level of 0.05.

Building on Burgess's (1925) concentric zone theory, Shaw and McKay (1930) developed social disorganization theory. Social disorganization of neighborhoods is, according to Shaw and McKay (1942), characterized by a combination of persistent poverty, racial/ethnical heterogeneity, transiency (rapid/frequent population turnover), and urbanism, which in turn is fueling the disruption of core social institutions, such as the family, the church community, and schools. It was hypothesized that crime is more likely to occur in the core of the city and the enclosing zone in transition, with crime decreasing with the distance from the center. In the contemporary United States, an invert trend can be witnessed. Urban revitalization appears to invert Burgess's concentric zone theory and Shaw and McKay's (1930) social disorganization theory, with more and more wealthy and educated individuals moving back into the core. You want to test this inverse trend by analyzing the levels of perceived neighborhood problems (using a scale of 1-15, where 15 represents the highest level of perceived neighborhood problems) of a random sample of 40 individuals living in Minneapolis and its suburbs. Although Burgess's concentric zone theory entails five zones (central business district, zone in transition, working man, residential, and commuter), you decide to compare the mean levels of perceived neighborhood problems of residents from downtown, residential areas, and suburbs. You select an alpha level of 0.05. The descriptive information is presented in the table below.  Downtown  Residential  Suburbs 85137710591410111111688869101313612124111089686121214912712\begin{array} { | c | c | c | } \hline \text { Downtown } & \text { Residential } & \text { Suburbs } \\\hline 8 & 5 & 13 \\\hline 7 & 7 & 10 \\\hline 5 & 9 & 14 \\\hline 10 & 11 & 11 \\\hline 11 & 6 & 8 \\\hline 8 & 8 & 6 \\\hline 9 & 10 & 13 \\\hline 13 & 6 & 12 \\\hline 12 & 4 & 11 \\\hline 10 & 8 & 9 \\\hline 6 & 8 & 6 \\\hline 12 & 12 & 14 \\\hline 9 & & 12 \\\hline 7 & & \\\hline 12 & & \\\hline\end{array} a. Indicate which variable is the IV and which is the DV. Also indicate the level of measurement for each variable. b. State your null and alternative hypotheses. c. Compute: i. The group mean. ii. Grand mean. iii. Standard deviation for each group. iv. Sum of squares. v. The degrees of freedom (within and between). vi.f d. State the decision rule e. Make a decision and interpret your findings.

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You want to determine whether gender has an impact on attitudes toward police. You conduct a survey with a random sample of 220 individuals over the age of 18 asking your participants about their attitudes about police (positive/negative). The results are presented in the table below. You set your alpha level at 0.01. a. Identify the independent and dependent variables and indicate the level of measurement for each variable. b. Compute the percentages for every cell. c. State your null hypothesis and your alternative hypotheses. d. Compute the degrees of freedom. e. State your decision rule f. Compute expected frequencies for each cell. g. Compute chi square. h.Interpret your findings.  Male  Female  Positive 427793 Negative 574412799121220\begin{array} { | l | r | r | r | } \hline & { \text { Male } } & \text { Female } & \\\hline \text { Positive } & 42 & 77 & 93 \\\hline \text { Negative } & 57 & 44 & 127 \\\hline & 99 & 121 & 220 \\\hline\end{array}

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You rejected the null hypothesis for the following cases (2 × 2 tables) and thus found a real difference between the sample means. However, you want to know how strong the relationship is. a. Determine which test of association is appropriate for a chi square with two variables with two categories. b. Compute the strength of the relationship for the following and interpret your results. i. χ2 = 4.235; n = 153 ii. χ2 = 18.567; n = 215 iii. χ2 = 3.898; n = 310 iv. χ2 = 22.33; n = 146 v. χ2 = 10.659; n = 189 vi. χ2 = 29.66; n = 195

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a. The appropriate test of association is phi \[\phi = \sqrt { \frac { \chi ^ { 2 } } { n } }\] b. \[\begin{array} { l } \text { i. } \chi ^ { 2 } = 4.235 ; n = 153 \text {. } \\ \phi = \sqrt { \frac { 4.235 } { 153 } } = 0.17 \\ \end{array}\] 17% of the variance within the DV variable is explained by the IV, leaving 83% of the variance unexplained (explained by other variables). \[\begin{array} { l } \text { ii. } \chi ^ { 2 } = 18.567 ; n = 215 \\ - \phi = \sqrt { \frac { 18.567 } { 215 } } = 0.29 \end{array}\] 29% of the variance within the DV variable is explained by the IV, leaving 71% of the variance unexplained (explained by other variables). iii. \[\begin{array} { l } \chi ^ { 2 } = 3.898 ; n = 310 \\ \phi = \sqrt { \frac { 3.898 } { 310 } } = 0.11 \end{array}\] 11% of the variance within the DV variable is explained by the IV, leaving 89% of the variance unexplained (explained by other variables). iv. \(\quad \chi ^ { 2 } = 22.33 ; n = 146\). \[\phi = \sqrt { \frac { 22.33 } { 146 } } = 0.39\] 39% of the variance within the DV variable is explained by the IV, leaving 61% of the variance unexplained (explained by other variables). v. χ2 = 10.659; n = 189. \[\phi = \sqrt { \frac { 10.659 } { 189 } } = 0.24\] 24% of the variance within the DV variable is explained by the IV, leaving 76% of the variance unexplained (explained by other variables). \[\begin{array} { l } \text { i. } \chi ^ { 2 } = 29.66 ; n = 195 \text {. } \\ \phi = \sqrt { \frac { 29.66 } { 195 } } = 0.39 \end{array}\] vi. 39% of the variance within the DV variable is explained by the IV, leaving 61% of the variance unexplained (explained by other variables).

Now that you know about the attitudes of females and males toward police, you want to find whether there is also a relationship between gender (female/male) and official complaints filed (yes/no) after a citizen-police encounter. You send a follow-up survey to the participants already interviewed and 198 of 220 agree to answer the question of whether they have ever filed an official complaint after a citizen-police encounter (yes/no). The results are listed in the table below. This time you select an alpha level of 0.05. a. Identify the independent and dependent variables and indicate the level of measurement for each variable. b. Compute the percentages for every cell. c. State your null hypothesis and your alternative hypothesis. d. Compute the degrees of freedom. e. State your decision rule. f. Compute expected frequencies for each cell. g. Compute chi square. h. Interpret your findings.  Male  Female  Yes 234164 No 666813489109198\begin{array} { | l | r | r | r | } \hline & { \text { Male } } & \text { Female } & \\\hline \text { Yes } & 23 & 41 & 64 \\\hline \text { No } & 66 & 68 & 134 \\\hline & 89 & 109 & 198 \\\hline\end{array}

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